Question

If 280cm of hydrogen diffuses in 40 seconds how long will it take for 490cm of a gas(s) whose vapour density is 25 to diffuse under the same condition

Answer 1

Answer:

The time taken by gas x : 350 s

Further explanation  

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

Molar mass = 2 x vapour density(VD)

r₁=rate Hydrogen = 280 cm³ / 40 s = 7 cm³/s

M₁=molar mass Hydrogen=2 g/mol

M₂=molar mass gas x=

Explanation:

Hope this helps:)  ジョセフ

Answer 2

Answer:

gas(s) whose vapour density is 25 to diffuse under the same condition