if 291x+3y=0 and 4x-113y=0 then x+y=
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291x+3y=0 4x-113y=0
4x-113y=0
4x=113y
X=113y/4
put the value of X in first eqn
291(113y/4)+3y=0
32883y/4+3y/1=0
32883y-12y/4=0
32871y/4=0
y=0 therefore X= 0
note that whenever constant term is not there in the equation then the value of X and y will always 0
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