if 29the term of an ap is twice of its 18the term,then the 9th term is
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Question:-
➡ If 29th term of an AP is twice of its 18th term, then what is the 9th term?
Answer:-
➡ The 9th term of the AP is = 2d (equal to twice of common difference)
Solution:-
Given,
➡ 29th term of the AP is twice of its 18th term.
Let us assume that,
➡ First term = a
➡ Common difference = d
So,
➡ 29th term = a + (29 - 1)d
➡ 29th term = a + 28d
Now,
➡ 18th term = a + (18 - 1)d
➡ 18th term = a + 17d
According to the given condition,
➡ 29th term = 2 x 18th term
➡ a + 28d = 2(a + 17d)
➡ a + 28d = 2a + 34d
➡ a = -6d
Therefore,
9th term will be
= a + 8d
Substituting a, we get,
= -6d + 8d
= 2d
Which is the required answer.
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