Question

If 2a+1,6,3a+1 are in ap find the value of a

Answer 1

Answer:

Step-by-step explanation:

As they are in AP so there common differences will be same

X=2a+1

Y=6

Z=3a+1

Y-X= Z-X

6-2a-1 = 3a+1-6

5-2a =3a-5

10=5a

a=2

Answer 2

If 2a+1, 6, and 3a+1 are in AP, then
6-(2a+1)=3a+1-6
6-2a-1=3a-5
5a = 10
a=2