If 2a+3,a,3a+3 are the terms of A.P.Find the value of a?
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❇ Given, 2a + 3, a, 3a +3
If these terms are in A. P., then their common difference will be same.
So, a2 - a1 = a 3 - a2
a - ( 2a +3 ) = 3a +3 - a
-a - 3 = 2a +3
-3 - 3 = 2a +a
3a = - 6
a = - 6 / 3.
✔️a = - 2
❇ Given, 2a + 3, a, 3a +3
If these terms are in A. P., then their common difference will be same.
So, a2 - a1 = a 3 - a2
a - ( 2a +3 ) = 3a +3 - a
-a - 3 = 2a +3
-3 - 3 = 2a +a
3a = - 6
a = - 6 / 3.
✔️a = - 2
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