Question

if 2a, 3a+1,5a-4 are in A.P. , find the value of a describe this question solution​.

Answer 1

$\sf\red{\underline{\underline{Answer:}}}$

$\sf{The \ value \ of \ a \ is \ 6.}$

$\sf\orange{Given:}$

$\sf{\implies{2a, \ 3a+1, \ 5a-4 \ are \ in \ A.P.}}$

$\sf\pink{To \ find:}$

$\sf{The \ value \ of \ a.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Here,}$

$\sf{t1=2a, \ t2=3a+1, \ and \ t3=5a-4}$

$\boxed{\sf{2\times \ t2=t1+t3}}$

$\sf{\therefore{2(3a+1)=2a+5a-4}}$

$\sf{6a+2=7a-4}$

$\sf{6a-7a=-4-2}$

$\sf{-a=-6}$

$\sf{a=6}$

$\sf\purple{\tt{\therefore{The \ value \ of \ a \ is \ 6.}}}$

Answer 2

$\purple{\underline{\underline{\pink{\boxed{\boxed{\red{\star{\sf Question:}}}}}}}}$

$\rm{If \ 2a, \ 3a+1, \ 5a-4 \ are \ in \ AP ., \ Find \ the }$

$\rm{value \ of \ a }$

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$\purple{\underline{\underline{\orange{\boxed{\boxed{\green{\star{\sf Answer:}}}}}}}}$

$\rm{\red{\boxed{\blue{The \ value \ of \ a \ is \ 6.}}}}$

_________________________________________

$\sf\large\underline\pink{Given:}$

$\rm{\longrightarrow{2a, \ 3a+1, \ 5a-4 \ are \ in \ A.P.}}$

_________________________________________

$\sf\large\underline\blue{To \ Find}$

$\sf{The \ value \ of \ a.}$

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$\blue{\underline{\underline{\purple{\boxed{\boxed{\orange{\star{\sf Solution:}}}}}}}}$

$\rm{we \ are \ given,}$

$\rm{t1=2a, \ t2=3a+1, \ and \ t3=5a-4}$

$\rm{\orange{\boxed{\pink{\star{2\times \ t2=t1+t3}}}}}$

$\rm{\therefore{2(3a+1)=2a+5a-4}}$

$\rm{6a+2=7a-4}$

$\rm{6a-7a=-4-2}$

$\rm{-a=-6}$

$\rm{a=6}$

$\rm{\red{\boxed{\blue{The \ value \ of \ a \ is \ 6.}}}}$

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$\rm\red{Note: \ please \ ask \ this \ qué}$

$\rm\red{in \ math section}$

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$\rm\red{Hope \ it \ Helps \ :))}$