if 2a, 3a+1,5a-4 are in A.P. , find the value of a describe this question solution
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Answer:
a = 6
Step-by-step explanation:
given they are in a. p so they have
same common difference
so, a2-a1=a3-a2
3a+1-2a=5a-4-(3a+1)
a+1=5a-4-3a-1
a+1=2a-5
a-2a= -5-1
-a= -6
cancel the negative signs in both sides
so, a=6
Hope it's help you
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