Question

If 2a, 3a+1, 5a -4are in a.p.,find the value of a.

Answer 1

Answer:

given they are in a. p so they have

same common difference

so, a2-a1=a3-a2

3a+1-2a=5a-4-(3a+1)

a+1=5a-4-3a-1

a+1=2a-5

a-2a= -5-1

-a= -6

cancel the negative signs in both sides

so, a=6