Question

if 2a -3b = 10. ab = 16. Find 8a³-27​

Answer 1

Answer:

2a-3b=10

$a = \frac{10 + 3b}{2}$

ab=16______(i)

$(\frac{10 + 3b}{2} )b = 16$

$10b + {3b}^{2} = 32$

$10b + {3b}^{2} - 32$

${3b}^{2} + 10b - 32$

${3b}^{2} - 6b + 16b - 32$

3b(b-2)+16(b-2)

(3b+16)(b-2)

b=2

put the value of 'b' in

${eq}^{n} - (i)$

we get a=8

$now \: finding \: value \: of \: {8a}^{3} - 27$

$8 \times {8}^{3} - 27$

=8x512-27

=4069 answer..