If 2A+3B=[(2,3)(4,0)] and 3A+2B=[(-2,2)(1,-5)] find A and B.
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Answer:
Since, 2A+3B=[
2
4
−1
2
4
5
] …………(1)
A+2B=[
5
1
0
6
3
2
] ………….(2)
2× Equation (2)− Equation (1)
⇒2A+4B−2A−3B=[
10−2
2−3
0+1
12−2
6−4
4−5
]
⇒B=[
8
−1
1
10
2
−1
]
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