if 2a-3b =3 and ab=2,find the value of 2a*2a*2a-3b*3b*3b
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=(a2+b2)-(a-b)2
=(a2+b2)-(a2-2ab+b2)
removing brackets
=a2+b2-a2+2ab-b2
hence we get 2ab
therefore
2ab=(a2+b2)-(a-b)2
they have given the value of a2+b2=29 and a-b=3. substituting the value
2ab= 29-(3)2
=29-3*3
=29-9
2ab=20
ab=20/2
ab=10
I think you got me.. have a nice day..
=(a2+b2)-(a2-2ab+b2)
removing brackets
=a2+b2-a2+2ab-b2
hence we get 2ab
therefore
2ab=(a2+b2)-(a-b)2
they have given the value of a2+b2=29 and a-b=3. substituting the value
2ab= 29-(3)2
=29-3*3
=29-9
2ab=20
ab=20/2
ab=10
I think you got me.. have a nice day..
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