Question

If 2a+3b+4c=35 and 3a+5b+7c=30,then a+b+c=?

Answer 1

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here it is given.....
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2a+3b+4c=35 eq1
and 3a+5b+7c=30 eq2
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now... multiply eq1 by 2
then we get 4a+6b+8c=79 eq3
✅✅✅✅✅✅✅✅✅

now....
according to the question
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=> eq3 - eq2
=> (4a+6b+8c=70)-(3a+5b+7c=30)
=> a+b+c= 40
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answer of the question
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Answer 2

Here's your answer..

Solution:-

$2a + 3b + 4c = 35.........(1)$
$3a + 5b + 7c = 30.......(2)$
By subtracting equation (2) from (1),we get:-

$= > 3a + 5b + 7c = 30 \\ - \: \: \: 2a + 3b + 4c = 35$
__________________________
$= > a + 2b + 3c = - 5$
So,

$= > a + 2b + 3c = - 5........(3)$
Now,
By substitution equation(3) from (1) ,we get:-

$= > 2a + 3b + 4c = 35 \\ - \: \: \: \: a + 2b + 3c = - 5$
___________________________
$= > a + \: b \: + c \: = 40$
Hence,
a+b+b is 40

Hope it helps you...