If 2a+3b+4c=35 and 3a+5b+7c=30,then a+b+c=?
Answers
Answered by
11
❤❤❤hay.....❤❤❤
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here it is given.....
-------------------------
2a+3b+4c=35 eq1
and 3a+5b+7c=30 eq2
__________________
now... multiply eq1 by 2
then we get 4a+6b+8c=79 eq3
✅✅✅✅✅✅✅✅✅
now....
according to the question
-------------------------------------
=> eq3 - eq2
=> (4a+6b+8c=70)-(3a+5b+7c=30)
=> a+b+c= 40
@@@@@@@@@@@@@
answer of the question
➖➖➖➖➖➖➖➖➖
✔✔✔✔✔✔✔✔
plzzz.. mark it as a brainlist
⚓⚓⚓⚓⚓⚓⚓⚓⚓⚓
here it is given.....
-------------------------
2a+3b+4c=35 eq1
and 3a+5b+7c=30 eq2
__________________
now... multiply eq1 by 2
then we get 4a+6b+8c=79 eq3
✅✅✅✅✅✅✅✅✅
now....
according to the question
-------------------------------------
=> eq3 - eq2
=> (4a+6b+8c=70)-(3a+5b+7c=30)
=> a+b+c= 40
@@@@@@@@@@@@@
answer of the question
➖➖➖➖➖➖➖➖➖
Answered by
11
Here's your answer..
Solution:-
By subtracting equation (2) from (1),we get:-
__________________________
So,
Now,
By substitution equation(3) from (1) ,we get:-
___________________________
Hence,
a+b+b is 40
Hope it helps you...
Solution:-
By subtracting equation (2) from (1),we get:-
__________________________
So,
Now,
By substitution equation(3) from (1) ,we get:-
___________________________
Hence,
a+b+b is 40
Hope it helps you...
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