If 2A=3B=4C,then A:B:C=6:4:?___
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Let 2A = 3B = 4C = k(constant term).
2A = K
A = K/2 -------- (1)
3B = K
B = K/3 ------- (2)
4C = K
C = K/4 ------- (3)
On solving (1) & (2), we get
K/2 : K/3 : K/4
LCM of 2,3,4 = 12
K/6 : K/4: K/3
6:4:3.
Therefore A:B:C = 6:4:3.
Hope this helps!
2A = K
A = K/2 -------- (1)
3B = K
B = K/3 ------- (2)
4C = K
C = K/4 ------- (3)
On solving (1) & (2), we get
K/2 : K/3 : K/4
LCM of 2,3,4 = 12
K/6 : K/4: K/3
6:4:3.
Therefore A:B:C = 6:4:3.
Hope this helps!
Answered by
1
Hi,
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Please see the attached file!
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