Question

If 2a+ 3b-5c =0 , then prove that the point A(a) , B(b) , C(c) are collinear Hence, find the ratio in which the point C divides the line segment AB​

Answer 1

Answer:

Given,

2a+3b−5c=0

⇒2a+3b=5c

⇒52a+53b=c

⇒2+32a+3b=c

∴   point C(c) divides A(a) and B(b) internally in the ratio 2:3 and hence they are collinear as well.

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