Question

if 2a.3b.5c=2160 then evaluate [a+2b-3c]

Answer 1

Answer:

3A=2B=5C

Taking the LCM of 3, 2 & 5, we get 30.

Therefore,

30A/10 = 30B/15 = 30C/6

Dividing all by 30, we get,

A/10 = B/15 = C/6 = k(say)

A/10 = k => A = 10k

B/15 = k => B = 15k

C/6 = k => C = 6k

Now,

A : B : C = 10k : 15k : 6k

Removing k,

A : B : C = 10 : 15 : 6