Question

If 2A = 3B = 5C, then find A:B:C.​

Answer 1

Correct Question-:

• If 2A = 3B = 5C . Then , Find A:B:C .

AnswEr-:

• $\underline{\boxed{\star{\sf{\blue{ A:B:C = 15 : 10 : 6 .}}}}}$

EXPLANATION-:

• $\frak{Given \:-:}\begin{cases} \sf{The \: 2A = 3B = 5C .} \end{cases}$

• $\frak{To\:Find \:-:}\begin{cases} \sf{Find \: A : B : C .} \end{cases}$

Solution-:

$\frak{Let's \:Assume-:} \begin{cases} \sf{If \: 2A = 3B = 5C = k .} \end{cases}$

Then ,

• $\frak{A = \frac{k}{2} \:-:}\begin{cases} \sf{ 2A = k .}& \\\\ \sf{ A = \frac{k}{2}} \end{cases}$

• $\frak{B = \frac{k}{3} \:-:}\begin{cases} \sf{ 3B = k .}& \\\\ \sf{ B = \frac{k}{3}} \end{cases}$

• $\frak{C = \frac{k}{5} \:-:}\begin{cases} \sf{ 5C = k .}& \\\\ \sf{ C = \frac{k}{5}} \end{cases}$

$\dag{\frak{Then \:-:}}$

• $\underline{\boxed{\star{\sf{\blue{ A:B:C = \frac{k}{2} : \frac{k}{3} : \frac{k}{5} .}}}}}$

Then ,

• $\implies{\sf{\large { A:B:C = \frac{k}{2} : \frac{k}{3} : \frac{k}{5} }}}$

$\dag{\frak{We \:Know \: That -:}}\sf{L.C.M \: of\: 2,3\:and\:5 \:is \: 30.}$

• $\implies{\sf{\large { A:B:C = \frac{k}{2} ×30 : \frac{k}{3} ×30: \frac{k}{5} ×30 }}}$

• $\implies{\sf{\large { A:B:C = 15k:10k:6k}}}$

$\dag{\frak{Then \:-:}}$

• $\implies{\sf{\large { A:B:C = 15:10:6}}}$

Hence ,

• $\underline{\boxed{\star{\sf{\blue{ A:B:C = 15 : 10 : 6 .}}}}}$

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Answer 2

Answer:

$i \: hope \: it \: helps \: u \: plz \: mak \: me \: as \: a \: brainliest$