Question

if 2a=3b=6c,then find the relation between a,b and c

Answer 1

Let 2a = 3b = 6c = k

From (1) and (4)

2a = k

=> 2 = k / a ----(1)

From (2) and (4)

3b = k

=> 3 = k / b ----(2)

From (3) and (4)

6c = k

=> 6 = k / c -----(3)

Now,

We know that,

6 = 3 × 2

On putting the values, we get


k / c = k / a × k / b

=> 1 / c = k / ab

=> 1/ c = 6 c / ab [ k = 6c]

=> 6 c^2 = ab

=> ab / c^2 = 6

Answer 2

Hello friends!!

Here is your answer :

Let 2a = 3b = 6c = k

2a = k

$2 = \frac{k}{a}$

3b = k

$3 = \frac{k}{b}$

6c = k

$6 = \frac{k}{c}$

We know that,

6 ÷ 3 = 2

$\frac{k}{c} \div \frac{k}{b} = \frac{k}{a}$

$\frac{k}{c} \times \frac{b}{k} = \frac{k}{c}$

$\frac{b}{c} = \frac{k}{a}$

[k = 6c]

b/c = 6c/a

b(a) = 6c(c)

ab = 6c²

ab/c² = 6


Hope it helps you... ☺️☺️☺️☺️

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