If 2a=3b=6c .then prove c=ab/a+b
Answers
Answered by
12
Heyy mate ❤✌✌❤
Here's your Answer .....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Let 2a = 3b = 6c = x.
Therefore,
2a = x
=> a = x/2.
3b = x
=> b = x/3
6c = x
=> c = x/6
R.H.S.
ab/a+b
=> (x/2 × ×/6) ÷ x/2 + x/3
=> x^2/6 ÷ (3x + 2x)/6
=> x^2/ 5x
=> x/5
=> x /5 is not equal to c.
✔✔✔
Here's your Answer .....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
Let 2a = 3b = 6c = x.
Therefore,
2a = x
=> a = x/2.
3b = x
=> b = x/3
6c = x
=> c = x/6
R.H.S.
ab/a+b
=> (x/2 × ×/6) ÷ x/2 + x/3
=> x^2/6 ÷ (3x + 2x)/6
=> x^2/ 5x
=> x/5
=> x /5 is not equal to c.
✔✔✔
Answered by
9
let
2a=3b=6c=k
compare 2a=k=>a=k/2
similarly for b and c,
a=k/2
b=k/3
c=k/6
Now we have to prove
c=ab/a+b
k/6= k/2*k/3/k/2+k/3
k/6=k²/6*6/5k
k/6=k/5
k=0
then
c=0
2a=3b=6c=k
compare 2a=k=>a=k/2
similarly for b and c,
a=k/2
b=k/3
c=k/6
Now we have to prove
c=ab/a+b
k/6= k/2*k/3/k/2+k/3
k/6=k²/6*6/5k
k/6=k/5
k=0
then
c=0
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