Math, asked by deshankhanikar, 1 year ago

If 2a=3b=6c .then prove c=ab/a+b

Answers

Answered by AJThe123456
12
Heyy mate ❤✌✌❤

Here's your Answer .....

⤵️⤵️⤵️⤵️⤵️⤵️⤵️

Let 2a = 3b = 6c = x.

Therefore,

2a = x
=> a = x/2.

3b = x
=> b = x/3

6c = x
=> c = x/6

R.H.S.

ab/a+b

=> (x/2 × ×/6) ÷ x/2 + x/3

=> x^2/6 ÷ (3x + 2x)/6

=> x^2/ 5x

=> x/5

=> x /5 is not equal to c.
✔✔✔
Answered by vyaswanth
9
let

2a=3b=6c=k

compare 2a=k=>a=k/2
similarly for b and c,
a=k/2
b=k/3
c=k/6

Now we have to prove

c=ab/a+b

k/6= k/2*k/3/k/2+k/3

k/6=k²/6*6/5k

k/6=k/5

k=0

then

c=0

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