if 2a =3b=6c then show that c=ab/a+b
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2
a
=3
b
=6
c
alog2=blog3=clog6=K(say)
∴C=
log6
K
and log2=
a
K
and log3=
b
K
∴C=
log2+log3
K
=
K/a+K/b
K
∴C=
a+b
ab
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