if 2a+3b=7 and ab = 2 ,find 4a^2+9b^2
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Given : 2a+3b=7
squaring on both sides
(2a+3b)²=(7)²
using (a+b)²=a²+b²+2ab
(2a)²+(3b)²+2(2a)(3b)=49
4a²+9b²+12ab=49
4a²+9b²+12(2)=49
4a²+9b²+24=49
4a²+9b²=49-24
4a²+9b²=25
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