Math, asked by anoushkashakshi, 1 year ago

If 2A=3B and 4B=5C,then find A:C

Answers

Answered by gokul451
162
SOLN;
At first taken,
2A=3B
=>A=3B/2.
Then, taken 4B=5C.
=>C=4B/5
So A:C,
3B/2;4B/5,
THE FINAL ANS IS,
A;C=3/2;4/5

2092000: given that,
2092000: GIVEN THAT, 2A=3B AND 4B=5C. MULTIPLY BOTH LHS AND RHS OF 2A=3B WITH 4 AND 4B=5C WITH 3. AFTER MULTIPLYING WE GET 8A=12B AND 12B=15C. => 8A=15C => A:C=15:8
Answered by hotelcalifornia
47

Answer:

The value of A: C is \frac {3}{2} : \frac{4}{5}

To find:

The ratio of A: C if 2A=3B and 4B=5C

Solution:

Ratio must be expressed by comparing two similar quantities.

Note:  

1. We cannot compare the ratios by using two dissimilar quantities

2. Ratios can be expressed by using similar quantities and same units.

3. Always ratios are expressed in the lowest terms.

Given that

2A=3B and 4B=5C

In the above given equations, B is the common, so by solving both equations we can find A:C.

2A=3B

\begin{array} { c } { \mathrm { A } = \frac { 3 } { 2 } \mathrm { B } } \\\\ { 4 \mathrm { B } = 5 \mathrm { c } } \\\\ { \mathrm { C } = \frac { 4 } { 5 } \mathrm { B } } \\\\ { \mathrm { A } : \mathrm { C } = ? } \end{array}

Therefore,

\begin{array} { c } { A : C = \frac { 3 } { 2 } B : \frac { 4 } { 5 } B } \\\\ { A : C = \frac { 3 } { 2 } : \frac { 4 } { 5 } } \end{array}

The value of A: C is \frac {3}{2} : \frac{4}{5}

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