Math, asked by DeepakTiwari8159, 6 months ago

If 2a+7b=11 and ab=2, find the value of 4a^2+49b^2.

Answers

Answered by HimanshuMahiya

24

Answer:

65

Step-by-step explanation:

2a+7b=11, ab=2

(2a+7b)² =4a²+49b²+28ab

(11)² =4a²+49b²+28×2

121 =4a²+49b²+56

121-56 =4a²+49b²

65 =4a²+49b²

Answered by mmonajyadav

15

Answer:

Step-by-step explanation:

4a^2+49b^2

= (2a^2+7b^2)^2

= (2a+7b)^2 -2.2a.7b

= (11 )^2-2.14ab

= 121 -2.14.2

= 121 - 56

= 65

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