If 2a + b = 11 and ab = 24, find the value of
4a2 + b2.
Answers
Answered by
1
Answer:
4a^2 + b^2 = 73
Step-by-step explanation:
(2a + b)^2 = 11^2
4a^2 + 2(2a)(b) + b^2 = 121
4a^2 + 4ab + b^2 = 121
4a^2 + 4(24) + b^2 = 121
4a^2 + b^2 = 121 - 48
4a^2 + b^2 = 73
Answered by
1
(2a+b)^2=121
4a^2+b^2+4ab=121
4a^2+b^2+4(24)=121
4a^2+b^2+96=121
4a^2+b^2=121-96
4a^2+b^2=25
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