if 2a-b+c=0 prove that 4a^2-b^2+c^2+4ac=0
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Answered by
41
Hey friend, Harish here.
Here is your answer:
Given that ,
2a - b + c =0
To prove,
4a² - b² + c² + 4ac = 0
Proof,
2a - b + c =0
→ 2a +c = b
(Now, square both the sides)
→(2a +c )² = b²
→4a² + c² + 2(2a)(c) = b²
→4a² + c² + 4ac = b²
→4a² - b² + c ² + 4ac = 0.
Hence proved.
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Hope my answer is helpful to you. Pls mark as brainliest if u like my answer.
Here is your answer:
Given that ,
2a - b + c =0
To prove,
4a² - b² + c² + 4ac = 0
Proof,
2a - b + c =0
→ 2a +c = b
(Now, square both the sides)
→(2a +c )² = b²
→4a² + c² + 2(2a)(c) = b²
→4a² + c² + 4ac = b²
→4a² - b² + c ² + 4ac = 0.
Hence proved.
________________________________________________
Hope my answer is helpful to you. Pls mark as brainliest if u like my answer.
Rudransh111:
no roblem not but i will ask u if any problem
Answered by
12
Step-by-step explanation:
given: 2a - b + c = 0
prove that: 4a^2 - b^2 + c^2 + 4ac = 0
2a + c = b
(2a + c)^2 = (b)^2
4a^2 + c^2 + 4ac = b^2
4a^2 + c^2 + 4ac - b^2 =0
4a^2 - b^2 + c^2 + 4ac =0
hence, prove
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