Math, asked by Rudransh111, 1 year ago

if 2a-b+c=0 prove that 4a^2-b^2+c^2+4ac=0

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Answered by HarishAS
41
Hey friend, Harish here.

Here is your answer:

Given that ,

2a - b + c =0

To prove,

4a² - b² + c² + 4ac = 0

Proof,

2a - b + c =0

→ 2a +c = b

(Now, square both the sides)

→(2a +c )² = b²   

→4a² + c² + 2(2a)(c) = b²
 
→4a² + c²  + 4ac = b²

→4a² - b² + c ² + 4ac = 0.

Hence proved.
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Answered by prataprathor2008
12

Step-by-step explanation:

given: 2a - b + c = 0

prove that: 4a^2 - b^2 + c^2 + 4ac = 0

2a + c = b

(2a + c)^2 = (b)^2

4a^2 + c^2 + 4ac = b^2

4a^2 + c^2 + 4ac - b^2 =0

4a^2 - b^2 + c^2 + 4ac =0

hence, prove

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