if 2a-b+c=0 , prove that 4a^2-b^2+c^2+4ac=0
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Hey !!! It will definitely help you.
Given that,
2a - b + c = 0
shift -b to rhs, we get
2a + c = b
now squaring both sides,
(2a + c)² = (b)²
4a² + c²+ 2ac = b²
shift b² to LHS
4a²+ c² + 2ac -b²
Hence proved ❤️
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