If 2a-b+c=0 prove that 4a²-b²+c²+4ac=0
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Answer:
4a²-b²+c²+4ac=0
2a-b+c=0
Step-by-step explanation:
4a²- b² + c² + 4ac = 0
4a² + 4ac + c² = b²
(4a + 2c)(4a + 2c)/4 = b²
2(2a + c)2(2a + c)/4 = b²
(2a + c)(2a + c) = b²
(2a + c)² = b²
2a + c = b
2a - b + c = 0
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