Math, asked by rickysrivastava16, 9 months ago

If 2a-b+c=0 prove that 4a²-b²+c²+4ac=0


Answers

Answered by luisecubero77
3

Answer:

4a²-b²+c²+4ac=0

2a-b+c=0

Step-by-step explanation:

4a²- b² + c² + 4ac = 0

4a² + 4ac + c² = b²

(4a + 2c)(4a + 2c)/4 = b²

2(2a + c)2(2a + c)/4 = b²

(2a + c)(2a + c) = b²

(2a + c)² = b²

2a + c = b

2a - b + c = 0

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