Question

if 2a -b+c=0, prove that 4a²-b²+c²+4ac=0

Answer 1

my c and black one week and blue and gold

Answer 2

(√3)³ - 2×√3

2

= 3√3 - √3

= 2√3 ———>(i)

LHS = (√3 + 1)(3 - cot30°)

= (√3 + 1)(3 - √3)

= (√3 + 1) √3(√3 - 1)

= √3 [(√3)² - 1)]

= √3(3 - 1)

= 2√3 ———> (ii)

From (i) and (ii)

LHS = RHS