Question

If 2a – b + c =0 Prove that $\sf 4a²–b²+c²+4ac=0$

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Answer 1

Answer:

⏩hey mate here is ur answer..

If 2a – b + c =0 Prove that $\sf 4a²–b²+c²+4ac=0$

2a+c =b

2a+c =b=>(2a+c)²=b²

2a+c =b=>(2a+c)²=b²=>4a²+4ac+c²=b²

2a+c =b=>(2a+c)²=b²=>4a²+4ac+c²=b²=>4a²-b²+c²+4ac=0 [proved]

☮️hopes it helps you ..

tq

Answer 2

$\implies$In order to prove that $\rm[4a^{2}-b^{2}+c^{2}+4ac=0]$(eq2) It will be enough to prove that this equation is equal to the given equation(eq1):

$\rm{4a^{2}+c^{2}+4ac=b^{2}}$

$\rm{(2a+c)^{2}=b^{2}}$

$\rm{2a+c=b}$

$\rm{2a+c-b=0}$

From this we get eq1=eq2

$\large\bf{ Hence \: proved. }$

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$\tiny\tt{Hope \: this \: will \: help \: you }$