Question

if 2a -b+c=0 then show that 4a2 -b2+c2+4ac=0​

Answer 1

Answer:

2a+c=b

squaring both sides,

(2a+c)^2=b^2

4a^2+4ac+c^2=b^2

4a^2-b^2+c^2+4ac=0