Math, asked by manraj73, 11 months ago

If 2a25 is a multiple of 9,where a is a digit,what is the value of a?

#nswr plz

Answers

Answered by Anonymous
19

\huge\underline\mathcal{BONJOUR}

Your answer:-

Given,2a25 is a multiple of 9.

Divisibility rule of 9:Sum of all digits.

2+a+2+5=9+a

9+a is a multiple of 9.Here,we can choose any multiple of 9:9,18,27....81

9+a=9

a=9-9

a=0

OR

9+a=18

a=18-9

a=9

Hence,the possible numbers are 0 and 9.

Answered by sangeeta7paulsl
0

Answer:

The possible values of "a" are 0 and 9.

So, 2025 and 2925 are the numbers.

Step-by-step explanation:

2a25 is a multiple of 9

Solution:

Given, 2a25 is a multiple of 9.

Here, we have to find the value of "a" and also to check whether the number is divisible by 9 or not.

Divisibility rule of 9 :

The sum of all digits should be divisible by 9.

According to the divisibility rule,

=2+a+2+5

=9+a

9+a is a multiple of 9.

Here, we can choose any multiple of 9: 9,18,27....81

we can take only 9 and 18 , as they will give the value of "a" in single digit. otherwise the greater numbers like 27 and so on will give two digit numbers.

so in case 1 , we check by 9

9+a=9

⇒a=9−9

⇒a=0

Or

in case 2, we check by 18

9+a=18

⇒a=18−9

⇒a=9

In both the cases, the number is divisible by 9.

Hence, the possible value of "a" are 0 and 9. So, 2025 and 2925 are the numbers.

#SPJ2

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