Question

If 2AB = DE and BC = 8cm In similar triangles ΔABC and ΔDEF. then the value of EF is,
A. 12cm B.4cm C.16cm D.8cm

Answer 1

Answer:

EF = 16cm

Step-by-step explanation:

As ∆ABC and ∆DEF are similar,

→ $\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}$

Given that,

→ $\frac{AB}{DE} = \frac{1}{2}$

So,

→ $\frac{BC}{EF} = \frac{1}{2}$

from eq.2

→ $\frac{8}{EF} = \frac{1}{2}$

→ $EF = 16cm$