Question

If-2and 3 are the zeroes of quadratic x²+(p+1) x+q.them find the value of p and q.

Answer 1

Answer:

In the given equation $x^{2} +(p+1)x+q$, the value of $p=-2$ and $q=-6$

Step-by-step explanation:

Since it is given that $-2$ and $3$ are the zeros of the given polynomial,

we can write

$(x+2)(x-3)=x^{2} +(p+1)x+q=0$

that is , $x^{2} -x-6=x^{2} +(p+1)x+q$

now by comparing the corresponding coefficients we get,

$p+1=-1\ and\ q=-6$

that is , $p=-2\ and\ q=-6$.

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