Question

If 2and-3 are the zeroes of the quadratic polynomial xsquare +(a+1) x+b; hence find the values of a and b

Answer 1

Answer:

here is your answer and once try to solve it yourself

Answer 2

$\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}$

Actually Welcome to the Concept of the Quadratic Equation.

Now basically here we are going to use the, General form of the quadratic equation.

that is,

${x}^{2} -(alpha + beta)x + ( alpha*beta)$

where, a and b are roots of the equation, thus we get as,

=> (a+1) = -(alpha +beta)

=> (a+1) = -(2-3)

=> (a+1) = -(-1)

=> a+1 = 1

=> -(a +1)= -1

=> a = 0

=> and b = 2*(-3)

=> b = -6

thus value of a and b are,

⭐a = 0 and b= -6