Question

If 2and0 are the zero of the polynomial f(x)=2(x)ka cube-5(x)ka square+ax+b then find the value of a and b​

Answer 1

EXPLANATION.

→ 2 and 0 are the polynomial of the equation.

2x³ - 5x² + ax + b.

→ To find the value if A and B.

→ Case = 1.

→ Put the value of x = 2 in equation we get,

→ 2(2)³ - 5(2)² + a(2) + b = 0

→ 16 - 20 + 2a + b = 0

→ - 4 + 2a + b = 0

→ b = 4 - 2a .......(1)

→ Case = 2.

→ put the value of x = 0 in equation we get,

→ 2(0)³ - 5(0)² + a(0) + b = 0

→ 0 - 0 + 0 + b = 0

→ b = 0 ......(2)

→ Put the value of b = 0 in equation (1)

we get,

→ 0 = 4 - 2a

→ a = 2.

→ Value of A = 2 and B = 0.

Answer 2

Given :

• 2 and 0 are the polynomial of the equation.2x³ - 5x² + ax + b.

To find :

• The value if A and B.

Solution :

According to the Question :

• x = 2

➻ 2(2)³ - 5(2)² + a(2) + b = 0

➻ 2( 8) - 5(4) + 2a + b = 0

➻ 16 - 20 + 2a + b = 0

➻ - 4 + 2a + b = 0

➻ b = 4 - 2a .......(1)

• x = 0

Substitute all values :

➻ 2(0)³ - 5(0)² + a(0) + 4 - 2a = 0

➻ 2(0 )- 5(0) + 0 + 4 - 2a = 0

➻ 0 - 0 + 0 + 4 - 2a = 0

➻ a = 4 / 2

➻ a = 2

Hence the Value of A = 2 and B = 0.