Question

if 2b, (b-2) and 4b are in A.P. them what is the value of b?​

Answer 1

If these terms are in AP, their common difference is equal.

b - 2 - 2b = 4b - b + 2

-b - 2 = 3b + 2

-4 = 4b

b = -1

Answer 2

Aɴsᴡᴇʀ :

Given :

• A.P. = 2b , (b-2) and 4b

To Find :

• The value of b

Solution :

➪ It is given that following terms are in Arithmetic progression , therefore , common difference will be equal .

⠀⠀⠀• Common Difference = $\sf a_2\:-\: a_1$

➪ (b-2) - 2b = 4b - (b-2)

➪ b - 2 - 2b = 4b - b + 2

➪ - 2 - b = 3b + 2

➪ 3b + b = - 2 - 2

➪ 4b = - 4

➪ b = $\sf \:-\: \dfrac{4 }{4}$

➪ $\large\bold{\underline{\sf{\red{b\:=\:-\:1}}}}$

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