Question

) IF 2B91A7 is a 6-digit numberexactly divisible by 9 then the leastvalue of A+B is​

Answer 1

A number is divisible by 9 if the sum of it’s digits is divisible by 9.

So, 2+B+9+1+A+7 must be divisible by 9.

19+A+B= multiple of 9 near 19 and greater than 19= 27

A+B= 8

So least value of A+B = 8.