Math, asked by kittykatrivera2001, 1 year ago

) IF 2B91A7 is a 6-digit numberexactly divisible by 9 then the leastvalue of A+B is​

Answers

Answered by shashankreddy61002
0

A number is divisible by 9 if the sum of it’s digits is divisible by 9.

So, 2+B+9+1+A+7 must be divisible by 9.

19+A+B= multiple of 9 near 19 and greater than 19= 27

A+B= 8

So least value of A+B = 8.

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