) IF 2B91A7 is a 6-digit numberexactly divisible by 9 then the leastvalue of A+B is
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A number is divisible by 9 if the sum of it’s digits is divisible by 9.
So, 2+B+9+1+A+7 must be divisible by 9.
19+A+B= multiple of 9 near 19 and greater than 19= 27
A+B= 8
So least value of A+B = 8.
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