If 2by5 of a number exceeds 1by7 of the same number of 36 find the nu
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Let the number be x
2/5 of the no. = (2x/5)
1/7 of the no. = (x/7)
It is given that 2x/5 exceeds x/7 by 36
⇒ 2x/5 = (x/7)+36
⇒ 2x/5 - x/7 = 36
⇒ (14x - 5x)/35 = 36
⇒ 9x/35 = 36
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