if 〖2cos〗^2 θ+3sinθ-3=0 then find thr valu of sinθ in digree
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Answer:
Φ = 30 or 90
Step-by-step explanation:
Φ = 60±30
Step-by-step explanation:
Φ= angle
2cos²Φ + 3sinΦ - 3 = 0
we know that,
sin²Φ + cos²Φ = 1
cos²Φ = 1 - sin²Φ
2(1-sin²Φ) + 3sinΦ - 3 = 0
2 - 2sin²Φ + 3sinΦ -3 = 0
-2sin²Φ +3sinΦ -1 = 0
2sin²Φ - 3sinΦ + 1 = -1(0)
2sin²Φ - 3sinΦ + 1 = 0
2sin²Φ - 2sinΦ - sinΦ +1 = 0
2sinΦ(sinΦ - 1) -1 (sinΦ-1) = 0
(2sinΦ-1)(sinΦ-1) = 0
2sinΦ-1 = 0
sinΦ = ½
sinΦ = sin 30
Φ = 30°
Or
sinΦ= 1
SinΦ= sin 90
Φ = 90°
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