Math, asked by Rafiul3456, 3 months ago

if 〖2cos〗^2 θ+3sinθ-3=0 then find thr valu of sinθ in digree

Answers

Answered by triggeredboy793
0

Answer:

Φ = 30 or 90

Step-by-step explanation:

Φ = 60±30

Step-by-step explanation:

Φ= angle

2cos²Φ + 3sinΦ - 3 = 0

we know that,

sin²Φ + cos²Φ = 1

cos²Φ = 1 - sin²Φ

2(1-sin²Φ) + 3sinΦ - 3 = 0

2 - 2sin²Φ + 3sinΦ -3 = 0

-2sin²Φ +3sinΦ -1 = 0

2sin²Φ - 3sinΦ + 1 = -1(0)

2sin²Φ - 3sinΦ + 1 = 0

2sin²Φ - 2sinΦ - sinΦ +1 = 0

2sinΦ(sinΦ - 1) -1 (sinΦ-1) = 0

(2sinΦ-1)(sinΦ-1) = 0

2sinΦ-1 = 0

sinΦ = ½

sinΦ = sin 30

Φ = 30°

Or

sinΦ= 1

SinΦ= sin 90

Φ = 90°

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