If 2cos^2theta +sin theta-2=0 and 0°great than or equal to theta greater than or equal to 90°;find the value of theta
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Answer:
theta = 30°
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Answer:
The value of theta(θ) is 30°
Step-by-step explanation:
2cos²θ+sinθ−2=0
or, 2−2sin²θ+sinθ−2−0
or, sinθ(−2sinθ+1)=0
Since θ=0, sinθ= 2/1
⇒θ=30°. [Since 0°<θ<90°]
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