If 2cos a =route 3, prove 3sin a - 4sin³a=1
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Answer:
cos × sin
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2cosA = √3
=> cosA = √3/2
=> cosA = cos(30°)
=> A = 30°
Now,
3 sinA - 4 sin^3(A) = 3 sin(30°) - 4 sin^3(30°)
= 3(1/2) - 4(1/2)^3
= 3/2 - 1/2
= 2/2
= 1
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