) If 2cos0 -11cos + 5 = 0 then find factor.
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Answer:
Let △=
∣
∣
∣
∣
∣
∣
∣
∣
C
1
6
1
C
1
0
1
C
∣
∣
∣
∣
∣
∣
∣
∣
=C(C
2
−1)−1(C−6)=C
3
−2C+6
Put C=2cosθ we get
△=(2cosθ)
3
−2(2cosθ)+6
=8cos
3
θ−4cosθ+6
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