Math, asked by anamillyas246, 5 months ago

If 2cos3B =1 .Then the valuue of B is​

Answers

Answered by murtuzaqdr1
2

Answer:

cos3B=1/2

cos3B=cos60

3B=60

B=20

Answered by viny10
55

\huge\star\:\:{\orange{\underline{\purple{\mathcal{Answer}}}}}

\mathcal{\pink{\underbrace{\blue{Given :- }}}} 2cos 3B = 1

\mathcal{\pink{\underbrace{\green{To Find :-}}}}Value of B

\mathcal{\pink{\underbrace{\orange{Solution :- }}}}

2Cos 3B = 1

  \cos3b =  \frac{1}{2}

  =  > \cos(60)  =  \frac{1}{2}

 =  > 3b = 60

 =  > b =  \frac{60}{3}

 =  > b = 20

 \boxed {Value of B = 20}

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