If 2cosA=root3 then find 2cosA+1÷2cosA-1
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the value is 2 because cosA =root3 upon 2
then 2cosA +1 is 2*root 3 upon 2 so 2 and another 2 get cancelled so root3 +1 upon root 3 -1 when we rationalize it . it's and is 2
then 2cosA +1 is 2*root 3 upon 2 so 2 and another 2 get cancelled so root3 +1 upon root 3 -1 when we rationalize it . it's and is 2
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