If 2cotθ – 1 = 0, then find secθ – tanθ .
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Answered by
0
Answer:
Applying component and dividend, we get
2tanθ
2secθ
=
49−36
49+36
sinθ
1
=
13
85
Hence
sinθ=
85
13
Hence cosθ=
85
84
Hence
cosecθ=
13
85
and secθ=
84
85
Substituting in the above equation, we get
84+13
84−13
=
97
71
Answered by
0
Answer:
Thanks for the answer I was looking for iy
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