Question

if 2cot theta-1=0 then find
a).sin theta
b). cos theta
c).sec theta-tan theta
answers should be= 2/√5,1/√5 and √5-2 respectively.....
plzz help need it urgently
no other answers
plzz help.....​

Answer 1

Step-by-step explanation:

if 2 cos thetha -1=0

2costhetha=1

costheta=1/2=cos 60

so

thetha=60

a)sin thetha=sin 60=√3/2

b)cos thetha=cos 60=1/2

c)sec theta-tan thetha=sec 60-tan 60

=2-√3

this is your ans

Answer 2

Answer:

given that :-

2cot theta-1=0

2cot theta =1

cot theta=1/2

we kown that the formula

cot theta=p/b

Let,p=1 and b=2 then find h=?

By Pythagoras theorem

h^2= p^2+ b^2

=(1)^2 + (2)^2

= 1 + 4

h = √ 5

Now,

(a) Sin theta = p /h

=1/√5 Ans

(b) Cos theta= b/h

=2/√5

(c) sec theta- tan theta

h/b - b/p

√5/2 - 2/ √5

= 5 - 4/2√5

= 1/ 2√5

Ralionlise it

1/2√5 × 2/√5/ 2√5

= 2√5/20

= √5/10

Hope you helpul