Physics, asked by coolyoradhika2484, 11 months ago

If Ā = 2i+3j and B = 2j+3k the component B along A is
A)6
B)1/6
C)6/13
D)6/under root 13

Answers

Answered by shazai
12
A.B/[A]
=2(0)+3(2)+0(3)/root13
=6/root13
=option c
Answered by janu519
11

Answer:

hope that it will helps you

Attachments:
Similar questions