Physics, asked by coolyoradhika2484, 8 months ago

If Ā = 2i+3j and B = 2j+3k the component B along A is
A)6
B)1/6
C)6/13
D)6/under root 13

Answers

Answered by shazai
12
A.B/[A]
=2(0)+3(2)+0(3)/root13
=6/root13
=option c
Answered by janu519
11

Answer:

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