Question

IF Ā=2i+3j-k is a vector which makes an angle thita with y axis then thita is​

Answer 1

The angle between A and y-axis is tan⁻¹ (2/3)

A = 2i+3j

Now

A = |A| = √(2² + 3²) = √(4 + 9) = √(13)

Now, the cosine is given as:

cos β = (Adjacent side)/(Hypotenuse)

On substituting the values, we get,

cos β = 3/√(13)

Now, the sine is given as:

sin β = (Opposite side)/(Hypotenuse)

On substituting the values, we get,

sin β =  2/√(13)

Now, the angle between A and y axis is given as:

tan β = (Opposite side)/(Adjacent side)

On substituting the values, we get,

tan β = 2/3

∴ β = tan⁻¹ (2/3)

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Answer 2

Answer:

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