Physics, asked by Sarma12, 9 months ago

If (2i + 3j + xk) and (14i + 21j + 7k) are parallel, the value of x is​

Answers

Answered by manjushreesahu796
0

Explanation:

parallel vectors have proportional direction ratios

Therefore 14/2=21/3=7/x

Solving for x we get x=1

Answered by amitkumar44481
4

Correct Question :

Vector A = 2i + 3j + xk and Vector B 14i + 21j +7k. If A and B Vector are parallel, then find the value of x.

AnsWer :

1.

Solution :

  • When two vector parallel to then, a1/a2 = b1 /b2 = c1/c2.

Let the,

 \tt \vec{A} = 2 \hat{i} + 3 \hat{j} + x \hat{k}. \\ \tt  \vec{B} = 14 \hat{i} + 21 \hat{j} + 7 \hat{k}.

 \tt \frac{ a_1}{a_2} =  \frac{b_1 }{b _2 }  =  \frac{c _ 1}{c_2}

 \tt  \implies\frac{2}{14}  =  \frac{3}{21}  =  \frac{x}{7}

 \tt \implies \frac{ \cancel2}{ \cancel{14}}  =  \frac{ \cancel3}{ \cancel{21}}  =  \frac{x}{7}

 \implies \tt \frac{1}{7}  =  \frac{1}{7}  =  \frac{x}{7}

 \implies \tt \frac{1}{7}  =  \frac{x}{7}

 \implies \tt x =  \frac{\cancel7}{\cancel7}

 \tt \implies x = 1.

Therefore,the value of x be 1.

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