Question

If 2k+1,13, 5k-3 are three consecutive terms of A.P then k=

Answer 1

Answer:

Step-by-step explanation:

We know that a2 -a1 = a3 - a2

Therefore 13 - (2k +1) = 5k -3 -13

12 - 2k = 5k -16

7k - 28 = 0

Therefore.......

7k = 28

|||||| k = 4 ||||| -----------------> SOLUTION..

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Answer 2

Answer:

2b=a+c

16=2k+1+5k-3

=7k -2

16=7k-2

18=7k

K=18/7

*Or*

13-2k+1=5k-3-13

-7k = -4-26

=-30

K=30/7

The and is one of this...