Question

if 2k+1,3k and 5k-4 are in arithmetic progression(A.p),find k​

Answer 1

Answer:

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Step-by-step explanation:

2k + 1 = a

3k + 3 = b

5k - 1= c

To form an AP,

a + c = 2b

2k + 1 + 5k - 1 = 2( 3k + 3)

7k = 6k + 6

k = 6

So, k = 6

Hope This Helps You!

Answer 2

a1 = 2k+1

a2 = 3k

a3 = 5k-4

a2-a1 = d

a3-a2 = d

a3-a2 = a2-a1

5k-4-3k = 3k-2k-1

2k-4 = k-1

2k-k = -1+4

K = 3